$$\frac{m v^2}{r} =μ_sn mg\cos\theta$$

$$\frac{(1282\text{ kg}) (25\text{ m/s})^2}{(60\text{ m})} =(μ_s)(1282\text{ kg})(9,8 \text{ m/s}^2) (\cos33.7\grado)$$

$$33333\testo{ N} =(μ_s)(12601\testo{ N})$$

$$μ_s =2,65$$